Udal Filmyzilla Best – Easy & Working
def display_results(ranked_movie_list): for movie in ranked_movie_list: print(f"Title: {movie['title']}, Quality: {movie['quality']}")
def filter_and_rank_results(movie_data_list): # Filter movies available on Filmyzilla and rank based on quality or user reviews filtered_data = [movie for movie in movie_data_list if movie['filmyzilla_available']] # Simple ranking based on a hypothetical 'quality_score' ranked_data = sorted(filtered_data, key=lambda x: x['quality_score'], reverse=True) return ranked_data udal filmyzilla best
def check_filmyzilla_availability(title): url = f"https://www.filmyzilla.site/{title}" response = requests.get(url) soup = BeautifulSoup(response.content, 'html.parser') # Logic to check if movie is available return True # Placeholder key=lambda x: x['quality_score']
def fetch_movie_data(title): # Using TMDb API as an example tmdb_api_key = "YOUR_API_KEY" response = requests.get(f"https://api.themoviedb.org/3/search/movie?api_key={tmdb_api_key}&query={title}") return response.json() udal filmyzilla best
# Example usage movie_data = fetch_movie_data("Udal") print(movie_data) This step involves filtering the results based on their availability on Filmyzilla and ranking them. For simplicity, assume we have a list of dictionaries containing movie information and a boolean indicating Filmyzilla availability.
import requests from bs4 import BeautifulSoup
# Assuming movie_data_list contains processed data with 'filmyzilla_available' key # ranked_movie_list = filter_and_rank_results(movie_data_list) Finally, display the ranked results to the user.
